Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:12Z

∇²n = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

273K

6t² + 6t + 4 = 0

263K

9r² + 4r + 1 = 0

iħ ∂ψ/∂t = Ĥψ

139K

det| 9 4 ; 1 10 | = 86

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∑_{k=1}^{n} k = n(n+1)/2

333K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

160K

F = G m₁m₂ / r²

439K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

413K