Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 20:24Z
∑_{k=1}^{n} k = n(n+1)/2
det| 3 1 ; 7 4 | = 5
451K
det| 8 9 ; 3 9 | = 45
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 7 4 ; 4 8 | = 40
48K
∑_{k=1}^{n} k = n(n+1)/2
411K
det| 2 3 ; 3 3 | = -3
∑_{k=1}^{n} k = n(n+1)/2
401K