Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:04Z

11n² + 5n + 4 = 0

∇ × E = −∂B/∂t

460K

3z² + 5z + 1 = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

F = G m₁m₂ / r²

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

4φ² + 6φ + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

det| 7 4 ; 4 8 | = 40

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

459K

10t² + 9t + 5 = 0

406K

∇²ω = 0

∇ × E = −∂B/∂t

181K

\oint_C \vec{F}\cdot d\vec{r} = 0

80K

d/dr [r^2] = 2r^1

∇²β = 0

359K

ΔS ≥ 0