Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 16:27Z
∂ψ/∂φ = 6ψ
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
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11ψ² + 2ψ + 6 = 0
λ = h/p
det| 9 4 ; 1 10 | = 86
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∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-α²) dα = √π / 2
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