Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:40Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

3z² + 5z + 1 = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

Fe₂O₃ + 3CO → 2Fe + 3CO₂

186K

\lim_{β\to 0} \frac{\sin β}{β} = 1

411K

4φ² + 6φ + 2 = 0

∇ × E = −∂B/∂t

448K

∫₀^∞ e^(-t²) dt = √π / 2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

d/dt [t^3] = 3t^2

459K

ω = 2πf

406K

∇²ω = 0

det| 4 8 ; 3 5 | = -4

181K

8ψ² + 7ψ + 0 = 0

80K

d/dr [r^2] = 2r^1

12n² + 2n + 2 = 0

359K

ΔS ≥ 0

8β² + 5β + 0 = 0

det| 12 6 ; 6 13 | = 120