Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 00:39Z

\binom{n}{k} = \frac{n!}{k!(n-k)!}

12θ² + 2θ + 6 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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d/dx [x^7] = 7x^6

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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8ψ² + 7ψ + 0 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

ω = 2πf

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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∇ × E = −∂B/∂t

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇²β = 0

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∇ × E = −∂B/∂t

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d/dt [t^3] = 3t^2

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∫₀^∞ e^(-α²) dα = √π / 2

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