Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:21Z

11n² + 5n + 4 = 0

\frac{12}{6} \sum_{i=1}^{n} i^{2}

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

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det| 7 4 ; 4 8 | = 40

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4φ² + 6φ + 2 = 0

3z² + 5z + 1 = 0

448K

e^{i\pi} + 1 = 0

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∫₀^∞ e^(-φ²) dφ = √π / 2

det| 5 3 ; 7 6 | = 9

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7r² + 8r + 5 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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∑_{k=1}^{n} k = n(n+1)/2

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