Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:07Z

∇²n = 0

∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

263K

9r² + 4r + 1 = 0

6r² + 3r + 1 = 0

139K

d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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∂α/∂ω = 3α

160K

11γ² + 3γ + 6 = 0

PV = nRT

439K

N₂ + 3H₂ ⇌ 2NH₃

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det| 9 4 ; 1 10 | = 86

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8x² + 2x + 7 = 0

128K

∑_{k=1}^{n} k = n(n+1)/2

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