Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-21 05:49Z

\binom{n}{k} = \frac{n!}{k!(n-k)!}

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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e^{i\pi} + 1 = 0

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iħ ∂ψ/∂t = Ĥψ

λ = h/p

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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det| 8 6 ; 7 9 | = 30

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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det| 5 9 ; 7 6 | = -33

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∑_{k=1}^{n} k = n(n+1)/2

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d/dt [t^3] = 3t^2

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iħ ∂ψ/∂t = Ĥψ

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10t² + 9t + 5 = 0

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det| 9 4 ; 1 10 | = 86

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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