Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z

∇²n = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∑_{k=1}^{n} k = n(n+1)/2

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9r² + 4r + 1 = 0

det| 9 4 ; 1 10 | = 86

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1θ² + 2θ + 6 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

d/dt [t^3] = 3t^2

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\lim_{r\to 0} \frac{\sin r}{r} = 1

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4t² + 3t + 3 = 0

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7r² + 8r + 5 = 0

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∇²β = 0

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6r² + 3r + 1 = 0

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2n² + 4n + 0 = 0

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