Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 20:39Z
det| 6 5 ; 4 7 | = 22
∑_{k=1}^{n} k = n(n+1)/2
460K
∇²φ = 0
\frac{9}{2} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
22K
F = ma
det| 1 4 ; 3 2 | = -10
406K
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
181K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∇²γ = 0
1φ² + 4φ + 5 = 0