Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:49Z

11n² + 5n + 4 = 0

PV = nRT

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

186K

det| 2 6 ; 0 3 | = 6

411K

4φ² + 6φ + 2 = 0

det| 10 7 ; 3 11 | = 89

448K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

d/dt [t^3] = 3t^2

459K

7r² + 8r + 5 = 0

406K

∇²ω = 0

det| 9 4 ; 1 10 | = 86

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

d/dr [r^2] = 2r^1