Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 00:44Z

d/dy [y^8] = 8y^7

∑_{k=1}^{n} k = n(n+1)/2

451K

∇²z = 0

264K

\lim_{x\to 0} \frac{\sin x}{x} = 1

N₂ + 3H₂ ⇌ 2NH₃

297K

10t² + 9t + 5 = 0

252K

d/dn [n^3] = 3n^2

F = ma

48K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

6t² + 4t + 0 = 0

iħ ∂ψ/∂t = Ĥψ

377K

det| 7 4 ; 4 8 | = 40

299K

\oint_C \vec{F}\cdot d\vec{r} = 0

N₂ + 3H₂ ⇌ 2NH₃

401K

1n² + 7n + 3 = 0

420K

10n² + 4n + 2 = 0

∇ × E = −∂B/∂t

109K

N₂ + 3H₂ ⇌ 2NH₃

184K