Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 10:08Z

∇²t = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

438K

\frac{8}{3} \sum_{i=1}^{n} i^{2}

det| 7 4 ; 4 8 | = 40

186K

PV = nRT

411K

CaCO₃ → CaO + CO₂

∑_{k=1}^{n} k = n(n+1)/2

448K

N₂ + 3H₂ ⇌ 2NH₃

22K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

6n² + 7n + 6 = 0

181K