Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 11:44Z
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
det| 9 4 ; 1 10 | = 86
438K
det| 6 4 ; 3 7 | = 30
det| 1 4 ; 3 2 | = -10
411K
ΔS ≥ 0
1z² + 3z + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
406K
7t² + 3t + 1 = 0
det| 11 5 ; 2 12 | = 122
det| 8 3 ; 4 9 | = 60