Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 17:11Z

det| 11 2 ; 2 12 | = 128

∇ × E = −∂B/∂t

460K

iħ ∂ψ/∂t = Ĥψ

438K

CaCO₃ → CaO + CO₂

8ψ² + 7ψ + 0 = 0

186K

2H₂ + O₂ → 2H₂O

411K

3θ² + 7θ + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

d/dt [t^3] = 3t^2

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

6n² + 7n + 6 = 0

459K

∂γ/∂z = 6γ

406K

2H₂ + O₂ → 2H₂O

∇ × E = −∂B/∂t

181K

det| 3 7 ; 2 4 | = -2

80K

∫₀^∞ e^(-z²) dz = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

359K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O