Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 01:51Z

12γ² + 2γ + 2 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇²ω = 0

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∑_{k=1}^{n} k = n(n+1)/2

∫₀^∞ e^(-α²) dα = √π / 2

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det| 4 2 ; 6 5 | = 8

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5φ² + 3φ + 0 = 0

8ψ² + 7ψ + 0 = 0

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det| 11 5 ; 0 12 | = 132

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ΔS ≥ 0

\lim_{γ\to 0} \frac{\sin γ}{γ} = 1

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∂z/∂φ = 7z

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∫₀^∞ e^(-y²) dy = √π / 2

d/dt [t^3] = 3t^2

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\frac{2}{2} \sum_{i=1}^{n} i^{2}

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∇ × E = −∂B/∂t

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