Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:04Z

N₂ + 3H₂ ⇌ 2NH₃

∂β/∂β = 6β

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∑_{k=1}^{n} k = n(n+1)/2

118K

9ψ² + 4ψ + 2 = 0

λ = h/p

43K

E = mc²

261K

d/dβ [β^6] = 6β^5

\frac{4}{6} \sum_{i=1}^{n} i^{2}

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e^{i\pi} + 1 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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det| 7 4 ; 4 8 | = 40

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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iħ ∂ψ/∂t = Ĥψ

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N₂ + 3H₂ ⇌ 2NH₃

112K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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