Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:40Z

∑_{k=1}^{n} k = n(n+1)/2

3x² + 5x + 7 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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e^{i\pi} + 1 = 0

det| 8 9 ; 4 9 | = 36

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2H₂ + O₂ → 2H₂O

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2H₂ + O₂ → 2H₂O

∫₀^∞ e^(-x²) dx = √π / 2

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iħ ∂ψ/∂t = Ĥψ

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det| 4 8 ; 0 5 | = 20

det| 4 7 ; 2 5 | = 6

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\frac{4}{9} \sum_{i=1}^{n} i^{2}

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det| 4 7 ; 7 5 | = -29

8ψ² + 7ψ + 0 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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N₂ + 3H₂ ⇌ 2NH₃

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∇²ω = 0

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