Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 19:54Z

CH₄ + 2O₂ → CO₂ + 2H₂O

6t² + 6t + 4 = 0

460K

5φ² + 1φ + 1 = 0

438K

det| 1 1 ; 4 2 | = -2

det| 10 7 ; 3 11 | = 89

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

CaCO₃ → CaO + CO₂

∇ × E = −∂B/∂t

448K

F = G m₁m₂ / r²

22K

det| 8 4 ; 2 9 | = 64

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

CH₄ + 2O₂ → CO₂ + 2H₂O

406K

4n² + 8n + 6 = 0

det| 7 4 ; 4 8 | = 40

181K

12γ² + 9γ + 1 = 0

80K

6α² + 1α + 5 = 0

\oint_C \vec{F}\cdot d\vec{r} = 0

CH₄ + 2O₂ → CO₂ + 2H₂O