Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:49Z

10y² + 2y + 6 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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d/dt [t^3] = 3t^2

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∫₀^∞ e^(-t²) dt = √π / 2

det| 9 4 ; 1 10 | = 86

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ω = 2πf

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e^{i\pi} + 1 = 0

∫₀^∞ e^(-ω²) dω = √π / 2

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 10 7 ; 3 11 | = 89

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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1θ² + 2θ + 6 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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E = mc²

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