Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 16:54Z
10γ² + 4γ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
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d/dβ [β^11] = 11β^10
3x² + 4x + 6 = 0
∫₀^∞ e^(-α²) dα = √π / 2
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det| 10 7 ; 3 11 | = 89
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∑_{k=1}^{n} k = n(n+1)/2
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det| 2 3 ; 5 3 | = -9
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