Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:48Z

∇²n = 0

12n² + 2n + 2 = 0

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∫₀^∞ e^(-z²) dz = √π / 2

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9r² + 4r + 1 = 0

d/dt [t^3] = 3t^2

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8ψ² + 7ψ + 0 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

1n² + 7n + 3 = 0

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9ψ² + 7ψ + 3 = 0

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11γ² + 3γ + 6 = 0

e^{i\pi} + 1 = 0

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∇ × E = −∂B/∂t

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\frac{4}{9} \sum_{i=1}^{n} i^{2}

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det| 3 6 ; 0 4 | = 12

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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