Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 16:26Z
10γ² + 4γ + 3 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
438K
d/dβ [β^11] = 11β^10
∫₀^∞ e^(-α²) dα = √π / 2
411K
3x² + 4x + 6 = 0
det| 7 4 ; 4 8 | = 40
22K
CaCO₃ → CaO + CO₂
det| 4 7 ; 2 5 | = 6
459K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∑_{k=1}^{n} k = n(n+1)/2
F = ma
3n² + 3n + 5 = 0