Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 23:06Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

iħ ∂ψ/∂t = Ĥψ

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

∇ × E = −∂B/∂t

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8ψ² + 7ψ + 0 = 0

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ω = 2πf

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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N₂ + 3H₂ ⇌ 2NH₃

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e^{i\pi} + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

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CaCO₃ → CaO + CO₂

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∑_{k=1}^{n} k = n(n+1)/2

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d/dt [t^3] = 3t^2

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