Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:19Z
∇²n = 0
9r² + 4r + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\lim_{r\to 0} \frac{\sin r}{r} = 1
160K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
439K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
413K
∑_{k=1}^{n} k = n(n+1)/2
297K
det| 9 4 ; 1 10 | = 86
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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
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