Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:37Z

∇²t = 0

∫₀^∞ e^(-α²) dα = √π / 2

460K

PV = nRT

438K

det| 6 4 ; 3 7 | = 30

8ψ² + 7ψ + 0 = 0

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

ΔS ≥ 0

det| 12 6 ; 0 13 | = 156

448K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

22K

1z² + 3z + 2 = 0

∂ψ/∂β = 3ψ

459K

2H₂ + O₂ → 2H₂O

406K

7t² + 3t + 1 = 0

d/dt [t^3] = 3t^2

181K

det| 8 9 ; 4 9 | = 36

80K

∇ × E = −∂B/∂t

359K

N₂ + 3H₂ ⇌ 2NH₃

455K