Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:21Z

∇²n = 0

3x² + 5x + 7 = 0

273K

E = mc²

263K

9r² + 4r + 1 = 0

ω = 2πf

139K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

d/dφ [φ^1] = 1φ^0

333K

iħ ∂ψ/∂t = Ĥψ

160K

11γ² + 3γ + 6 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

439K

CH₄ + 2O₂ → CO₂ + 2H₂O

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

8ψ² + 7ψ + 0 = 0

297K

det| 10 2 ; 3 11 | = 104

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N₂ + 3H₂ ⇌ 2NH₃

404K

2n² + 4n + 0 = 0

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