Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:01Z

11n² + 5n + 4 = 0

∇²β = 0

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 4 7 ; 2 5 | = 6

186K

iħ ∂ψ/∂t = Ĥψ

411K

4φ² + 6φ + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

ω = 2πf

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 11 5 ; 0 12 | = 132

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

det| 9 4 ; 1 10 | = 86

181K

∇ × E = −∂B/∂t

80K

F = G m₁m₂ / r²

359K