Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 17:24Z

det| 11 2 ; 2 12 | = 128

∇ × E = −∂B/∂t

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

CaCO₃ → CaO + CO₂

10ψ² + 5ψ + 0 = 0

186K

d/dt [t^3] = 3t^2

411K

3θ² + 7θ + 1 = 0

F = ma

448K

8ψ² + 7ψ + 0 = 0

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\oint_C \vec{F}\cdot d\vec{r} = 0

459K

∂y/∂γ = 8y

406K

2H₂ + O₂ → 2H₂O

∇ × E = −∂B/∂t

∫₀^∞ e^(-z²) dz = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O