Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 14:24Z
3γ² + 8γ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
∫₀^∞ e^(-z²) dz = √π / 2
438K
PV = nRT
det| 7 4 ; 4 8 | = 40
186K
∑_{k=1}^{n} k = n(n+1)/2
411K
det| 1 9 ; 5 2 | = -43
ω = 2πf
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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∑_{k=1}^{n} k = n(n+1)/2
455K