Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 06:40Z
∑_{k=1}^{n} k = n(n+1)/2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
273K
∫₀^∞ e^(-x²) dx = √π / 2
263K
e^{i\pi} + 1 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
108K
2H₂ + O₂ → 2H₂O
det| 9 4 ; 1 10 | = 86
333K
det| 4 8 ; 0 5 | = 20
CH₄ + 2O₂ → CO₂ + 2H₂O
439K
∑_{k=1}^{n} k = n(n+1)/2
413K