Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:41Z

10y² + 2y + 6 = 0

10β² + 4β + 1 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∫₀^∞ e^(-t²) dt = √π / 2

∫₀^∞ e^(-t²) dt = √π / 2

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det| 2 3 ; 5 3 | = -9

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e^{i\pi} + 1 = 0

F = G m₁m₂ / r²

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 9 4 ; 1 10 | = 86

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∫₀^∞ e^(-θ²) dθ = √π / 2

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F = G m₁m₂ / r²

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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iħ ∂ψ/∂t = Ĥψ

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7r² + 8r + 5 = 0

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