Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:39Z

10γ² + 4γ + 3 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

d/dβ [β^11] = 11β^10

∑_{k=1}^{n} k = n(n+1)/2

186K

det| 3 6 ; 0 4 | = 12

411K

3x² + 4x + 6 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

det| 7 4 ; 4 8 | = 40

22K

CaCO₃ → CaO + CO₂

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

e^{i\pi} + 1 = 0

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

∑_{k=1}^{n} k = n(n+1)/2