Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:50Z

11n² + 5n + 4 = 0

PV = nRT

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

8ψ² + 7ψ + 0 = 0

186K

2H₂ + O₂ → 2H₂O

411K

4φ² + 6φ + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

d/dt [t^3] = 3t^2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

d/dφ [φ^1] = 1φ^0

459K

PV = nRT

406K

∇²ω = 0

∇ × E = −∂B/∂t

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

d/dr [r^2] = 2r^1

det| 10 2 ; 3 11 | = 104

359K

ΔS ≥ 0