Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 16:24Z
∂ψ/∂φ = 6ψ
∑_{k=1}^{n} k = n(n+1)/2
451K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
264K
11ψ² + 2ψ + 6 = 0
\lim_{r\to 0} \frac{\sin r}{r} = 1
252K
λ = h/p
det| 9 4 ; 1 10 | = 86
48K
∫₀^∞ e^(-θ²) dθ = √π / 2
411K
\frac{9}{7} \sum_{i=1}^{n} i^{2}
\frac{2}{8} \sum_{i=1}^{n} i^{2}
8y² + 6y + 2 = 0