Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:07Z

∑_{k=1}^{n} k = n(n+1)/2

∇ × E = −∂B/∂t

273K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

263K

e^{i\pi} + 1 = 0

det| 5 3 ; 7 6 | = 9

139K

d/dt [t^3] = 3t^2

108K

2H₂ + O₂ → 2H₂O

8ψ² + 7ψ + 0 = 0

333K

N₂ + 3H₂ ⇌ 2NH₃

160K

det| 4 8 ; 0 5 | = 20

∑_{k=1}^{n} k = n(n+1)/2

439K

∑_{k=1}^{n} k = n(n+1)/2

413K

det| 4 7 ; 7 5 | = -29

PV = nRT

297K

\lim_{β\to 0} \frac{\sin β}{β} = 1

128K

10t² + 5t + 2 = 0

det| 1 6 ; 5 2 | = -28

F = ma

∇ × E = −∂B/∂t