Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:39Z

10γ² + 4γ + 3 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

∂z/∂φ = 7z

438K

d/dβ [β^11] = 11β^10

\lim_{r\to 0} \frac{\sin r}{r} = 1

186K

det| 7 2 ; 7 8 | = 42

411K

3x² + 4x + 6 = 0

8ψ² + 7ψ + 0 = 0

448K

∫₀^∞ e^(-α²) dα = √π / 2

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iħ ∂ψ/∂t = Ĥψ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

∫₀^∞ e^(-θ²) dθ = √π / 2

181K

∇ × E = −∂B/∂t

80K

d/dt [t^3] = 3t^2

359K