Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:34Z

11t² + 8t + 0 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

460K

d/dt [t^3] = 3t^2

438K

∂ω/∂β = 7ω

det| 4 8 ; 3 5 | = -4

186K

iħ ∂ψ/∂t = Ĥψ

411K

det| 3 3 ; 7 4 | = -9

8ψ² + 7ψ + 0 = 0

448K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

22K

PV = nRT

∇ × E = −∂B/∂t

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂