Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:38Z

11n² + 5n + 4 = 0

N₂ + 3H₂ ⇌ 2NH₃

460K

iħ ∂ψ/∂t = Ĥψ

438K

∫₀^∞ e^(-x²) dx = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

186K

N₂ + 3H₂ ⇌ 2NH₃

411K

4φ² + 6φ + 2 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

448K

det| 7 4 ; 4 8 | = 40

22K

∇²β = 0

459K

6t² + 6t + 4 = 0

406K

∑_{k=1}^{n} k = n(n+1)/2

181K

∫₀^∞ e^(-t²) dt = √π / 2

80K