Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 01:55Z

12γ² + 2γ + 2 = 0

10β² + 4β + 1 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

CH₄ + 2O₂ → CO₂ + 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

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5φ² + 3φ + 0 = 0

8ψ² + 7ψ + 0 = 0

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6t² + 6t + 4 = 0

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ΔS ≥ 0

∇ × E = −∂B/∂t

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∑_{k=1}^{n} k = n(n+1)/2

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det| 3 7 ; 2 4 | = -2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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d/dt [t^3] = 3t^2

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iħ ∂ψ/∂t = Ĥψ

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