Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-09-19 00:23Z

∇ × E = −∂B/∂t

∂ψ/∂α = 5ψ

398K

d/dφ [φ^1] = 1φ^0

335K

1α² + 5α + 4 = 0

1γ² + 1γ + 6 = 0

156K

ω = 2πf

38K

d/dy [y^11] = 11y^10

\lim_{β\to 0} \frac{\sin β}{β} = 1

15K

3r² + 5r + 6 = 0

328K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

∫₀^∞ e^(-θ²) dθ = √π / 2

382K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

378K

e^{i\pi} + 1 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

190K

∑_{k=1}^{n} k = n(n+1)/2

242K

∫₀^∞ e^(-α²) dα = √π / 2

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iħ ∂ψ/∂t = Ĥψ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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