Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z
∇²n = 0
9r² + 4r + 1 = 0
∫₀^∞ e^(-x²) dx = √π / 2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-θ²) dθ = √π / 2
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11γ² + 3γ + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
439K
det| 4 8 ; 3 5 | = -4
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det| 7 4 ; 4 8 | = 40
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