Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 17:28Z

det| 11 2 ; 2 12 | = 128

det| 8 9 ; 4 9 | = 36

460K

∫₀^∞ e^(-z²) dz = √π / 2

438K

CaCO₃ → CaO + CO₂

d/dt [t^3] = 3t^2

186K

8ψ² + 7ψ + 0 = 0

411K

3θ² + 7θ + 1 = 0

\frac{12}{6} \sum_{i=1}^{n} i^{2}

448K

det| 2 6 ; 0 3 | = 6

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

∇ × E = −∂B/∂t

406K

N₂ + 3H₂ ⇌ 2NH₃

181K

iħ ∂ψ/∂t = Ĥψ

80K

∑_{k=1}^{n} k = n(n+1)/2

359K

∇ × E = −∂B/∂t

455K