Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:39Z

∑_{k=1}^{n} k = n(n+1)/2

E = mc²

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iħ ∂ψ/∂t = Ĥψ

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det| 8 9 ; 3 9 | = 45

2n² + 4n + 0 = 0

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det| 7 4 ; 4 8 | = 40

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

F = G m₁m₂ / r²

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\frac{4}{9} \sum_{i=1}^{n} i^{2}

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det| 2 3 ; 3 3 | = -3

det| 5 3 ; 7 6 | = 9

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det| 9 8 ; 3 10 | = 66

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∑_{k=1}^{n} k = n(n+1)/2

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∇ × E = −∂B/∂t

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