Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 02:49Z

det| 5 4 ; 6 6 | = 6

∇ × E = −∂B/∂t

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\oint_C \vec{F}\cdot d\vec{r} = 0

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∇²φ = 0

det| 10 7 ; 3 11 | = 89

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det| 12 2 ; 2 13 | = 152

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det| 12 5 ; 4 13 | = 136

F = G m₁m₂ / r²

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∇²ω = 0

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∑_{k=1}^{n} k = n(n+1)/2

det| 7 4 ; 4 8 | = 40

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∇²θ = 0

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2H₂ + O₂ → 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

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CH₄ + 2O₂ → CO₂ + 2H₂O

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