Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 03:18Z

det| 7 6 ; 7 8 | = 14

N₂ + 3H₂ ⇌ 2NH₃

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∫₀^∞ e^(-θ²) dθ = √π / 2

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F = G m₁m₂ / r²

8ψ² + 7ψ + 0 = 0

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∂α/∂ω = 3α

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det| 10 3 ; 0 11 | = 110

det| 12 6 ; 0 13 | = 156

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∇²z = 0

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∂x/∂α = 8x

iħ ∂ψ/∂t = Ĥψ

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\lim_{r\to 0} \frac{\sin r}{r} = 1

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∇ × E = −∂B/∂t

d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇ × E = −∂B/∂t

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11φ² + 4φ + 0 = 0

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