Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 15:37Z
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
N₂ + 3H₂ ⇌ 2NH₃
\oint_C \vec{F}\cdot d\vec{r} = 0
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det| 9 8 ; 3 10 | = 66
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\oint_C \vec{F}\cdot d\vec{r} = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 5 2 ; 3 6 | = 24
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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∫₀^∞ e^(-ω²) dω = √π / 2
∇ × E = −∂B/∂t
∂n/∂ω = 2n
N₂ + 3H₂ ⇌ 2NH₃