Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 17:26Z

det| 11 2 ; 2 12 | = 128

∑_{k=1}^{n} k = n(n+1)/2

460K

∇ × E = −∂B/∂t

438K

CaCO₃ → CaO + CO₂

Fe₂O₃ + 3CO → 2Fe + 3CO₂

186K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

411K

3θ² + 7θ + 1 = 0

8ψ² + 7ψ + 0 = 0

448K

d/dt [t^3] = 3t^2

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

2H₂ + O₂ → 2H₂O

∇ × E = −∂B/∂t

∫₀^∞ e^(-z²) dz = √π / 2