Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 16:47Z
10γ² + 4γ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
∑_{k=1}^{n} k = n(n+1)/2
438K
d/dβ [β^11] = 11β^10
det| 9 4 ; 1 10 | = 86
186K
3x² + 4x + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
181K
∑_{k=1}^{n} k = n(n+1)/2
359K